Serial Dilution Problem - what's the needed dilution? | ||
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Remember, 1 mL of the stock solution = x mL of the working solution. Solve for x, and you have your answer! To check it, put the cursor in the black box at the bottom of the screen. To get more problems, click on 'New Question'. When you're sure you know how to do this, click 'Forward' to go on and do integrated problems. |
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